Re: Howto implement bootchooser <-> rauc interaction

[Ahmad Fatoum <a.fatoum@pengutronix.de>]

Hi,

On 17.12.21 13:43, Konstantin Kletschke wrote:
> Hi :-)
> 
> On Fri, Dec 17, 2021 at 10:46:42AM +0100, Ahmad Fatoum wrote:
>  
>> It was backported to stable in v5.10.20. Backport commit is 663a18271.
> 
> Sorry my git/google-foo is unsufficient, how do I get my hands on this
> commit?

  git remote add stable git://git.kernel.org/pub/scm/linux/kernel/git/stable/linux.git
  git fetch stable --tags
  git cherry-pick 663a18271

Or just update to a more recent kernel release.

> So, just to be shure for the state OF partition placed after the MBR before 1st
> MBR partition:
> 
> If I have 1st partition's start sector being 2048 I hafe plenty of room
> before this after the MBR.
> 
> The barebox state OF partition should be in there and I could place it
> at
> 
> reg = <0x300 0xfffff>
>
> because the MBR ends at 0x1ff and the 1st partition starts at
> sector 2048 ( 2048*512byte=1MB=0x10000), is that correct, is the reg
> addressing done this way?

Nope. offset(0x300) + size(0xfffff) > 0x10000, so it overlaps MBR partition.

If you really want an OF partition starting at byte offset 0x300 and ending
at 0xffffff includsive, you'd do

  reg = <0x300 0xffd00>;

> Of course a length of 0xfffff is far too much,
> just to get a picture. Also to transfer this to an OF partition in a MBR
> partition.
> 
> The container partition reg = <0xc0000 0x40000> in imx6qdl-prti6q-emmc.dtsi seems
> to be directly going to below a MBR partiton starting at 2048th sector
> with size 256kB, correct?  

Could be. You'd have to know how the on-disk partition table looks like,
but I'd guess that partitions are aligned to 1M boundaries and this is
as you describe directly beneath it.

Cheers,
Ahmad
 
> Thanks for your patience!
> 
> Regards
> Konstantin
> 
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